Question

1）sinx+（根号3）cosx=根号2

Answer 1

1)sinx+（根号3）cosx=2(sinx*1/2+cosx*（根号3）/2)=2(sinx*sinπ/6+cosx*cosπ/6)=2sin(x+π/6)所以原式有2sin(x+π/6)=根号2x+π/6=2kπ+π/4,或x+π/6=2kπ+3π/4k取整数所以,x=2kπ+π/12或x=2kπ+7π/122）sin...