2x(x-3)-(x-3)(x+6)=x²+12
2个回答
2x(x-3)-(x-3)(x+6)=x²+12
2x^2-6x-(x^2+3x-18)=x^2+12
-9x+6=0
x= 2/3
相关问题
-12x^4+6x^2-3x^6=(-3x)·________
6x^4-13x^3+12x^2-12x+6
3X(X-2)=6X-12
3X(X-2)=6X-12
(12x^3-18x^2+6x)/(-6x)=
x^3*x^5*x+(x^3)^12+4(x^6)^2
计算:(12x^3-6x^2)/3x^2=
3x^3一(x^3一2x^2+18x)一3/1(6x^3一6x^2十12x)
30-3(3-X)=4X 3X+12*6=15X+12 4X-2(50-X)=20 12(X-13)=10(X+3) 1
[6(x-2)²+12(x+2)(x-2)-3(x-1)²(x-2)]÷[3(2-x)]