Question

、往100ml 0.1mol/L 的Al2(SO4)3溶液中加入 0.5mol/L的NaOH溶液,得到1.17克沉淀,则

Answer 1

NAOH溶液的体积可能:130ML或90ML

(1)AI2(SO4)3 0.1mol

(2)AI3+ + 3OH- ==AI(OH)3

n(AI3+)==1.17/78 ==0.015mol

n(NaOH)==0.015*3 == 0.045mol

V(NaOH)==0.045/0.5==0.09L

(3)AI3+ + 3OH- ==AI(OH)3

n(NaOH)==1.17*3/78 == 0.045mol

AI3+ + 4OH- ==AIO2- +2H2O

n(NaOH)=(0.02-0.015)*4==0.02mol

V(NaOH)=(0.045+0.02)/0.5 ==1.3L