Question

x^a=1,x^b=4,求x^3a+2b的值

Answer 1

x^a=1,x^b=4,求x^3a+2b的值

x^(3a+2b)

=x^3a*x^2b

=(x^a)^3*(x^b)^2

=16

x^2n=3,(x^3n)^4=______

(x^3n)^4

=(x^3n)^2*(x^3n)^2

=(x^2n)^3*(x^2n)^3

=729

已知10^a=5,10^b=6,求10^3a+2b的值

10^(3a+2b)

=10^3a*10^2b

=(10^a)^3*(10^b)^2

=4500

已知n为正整数,且x^2n=4,试求9(x^3n)^2-13(x^2)^2n的值

9(x^3n)^2-13(x^2)^2n

=9(x^2n)^3-13(x^2n)^2

=576-208

=368