楼上方法非常好
若sin(x/2)-cos(x/2)=3/根5且180=
2个回答
相关问题
-
若sin(x-π)=2cos(2π-x),求(sin(π-x)+5cos(2π-x))/(3cos(π-x)-sin(-
-
若sinα,sinβ是方程x^2—((√2)cos20°)x+(cos20°)^2—1/2=0的两根,且sinα
-
f(x) =根2sin(x) + 根2cos(x) + 3
-
(1)√sin^2 500°+sin^2 770°-cos^2(180°-x) (180°
-
(sin(180°+2x))/(1+cos2x)*(cos2x0/(cos(90°+x))=
-
已知cos x=-1/3,且180°<x<270°.(1)求sin2x,cos2x,tan2x的值.(2)求sinx/2
-
已知向量a=(cos3/2x,sin3/2x),b=(cos1/2x,-sin1/2x),且x∈[0,派/2],若f(x
-
若f'(cos^2x)=sin^2x,且f(0)=-(1/2),求方程f(x)=0的根
-
sinx+sin3x+sin5x+.sin(2n-1)/cosx+cos3x+cos5x+.cos(2n-1)= sin
-
设f(x)=6cos^2x-根3sin2x