Question

（x八次方＋x六次方＋ x四次方＋x二次方＋1）的因式分解过程

Answer 1

(x^8+x^6+x^4+x^2+1)

=(x^2-1)(x^8+x^6+x^4+x^2+1)/(x^2-1)

=(x^10-1)/(x^2-1)

=(x^5+1)(x^5-1)/(x^2-1)

=(x+1)(x^4+x^3-x+1)(x-1)(x^4+x^3+x^2+x+1)/(x^2-1)

=(x^4+x^3-x+1)(x^4+x^3+x^2+x+1)