Question

如图,e是正方形abcd的边bc延长线上的一点,ce=ac,ae交cd于点f.·若ab=1cm,试求三角形abe的面积

Answer 1

S△ABE=BE*AB/2

=(CE+BC)*AB/2

=(AC+BC)*AB/2

=(√(AB²+BC²)+BC)*AB/2

=(√(1²+1²)+1)*1/2

=(1+√2)/2