Question

解分式方程2/x²+5x+6+3/x²+x-6=4/x²-4zh最后得10.

Answer 1

2(1/x+2 -1/x+3)+3/5(1/x-2 - 1/x+3)=1/x-2 -1/x+2

3/x+2 -(2+3/5)* 1/x+3 +(3/5-1)* 1/x-2=0

15/x+2 - 13/x+3 - 2/x-2=0

15(x+3)(x-2)-13(x+2)(x-2)-2(x+2)(x+3)=0

15(x²+x-6)-13(x²-4)-2(x²+5x+6)=0

5x=50

x=10