Question

求定义域 f（x）=6/x²-3x=2 f（x）=√4-x/x-1

Answer 1

分母不等于0

x²-3x+2≠0

(x-1)(x-2)≠0

x≠1,x≠2

所以定义域(-∞,1)∪(1,2)∪(2,+∞)

根号下大于等于,分母不等于0

(4-x)/(x-1)≥0

即(x-4)/(x-1)≤0

(x-4)(x-1)≤0

1≤x≤4

x-1≠0

所以1