f(1/2011)=alog2 1/2011-blog3 1/2011+2
=-alog2 2011+blog3 2011+2=4
所以alog2 2011-blog3 2011=-2
则f(2011)=alog2 2011-blog3 2011+2
=-2+2
=0
f(1/2011)=alog2 1/2011-blog3 1/2011+2
=-alog2 2011+blog3 2011+2=4
所以alog2 2011-blog3 2011=-2
则f(2011)=alog2 2011-blog3 2011+2
=-2+2
=0