x^2(2x+3)^2-34x(2x+3)-35=[x(2x+3)]^2-34x(2x+3)-35
=[x(2x+3)-35][x(2x+3)+1]
=(2x^2+3x-35)(2x^2+3x+1)
=(2x-7)(x+5)(2x+1)(x+1)
y^2-34y-35=（y-35)(y+1)
因式分解:a)因式分解y^2-34y-35 b) 由此,因式分解x^2(2x+3)^2-34x(2x+3)-35
x^2(2x+3)^2-34x(2x+3)-35=[x(2x+3)]^2-34x(2x+3)-35
=[x(2x+3)-35][x(2x+3)+1]
=(2x^2+3x-35)(2x^2+3x+1)
=(2x-7)(x+5)(2x+1)(x+1)
y^2-34y-35=（y-35)(y+1)