Question

(√3+i)的14次方/(1-√3i)的8次方

Answer 1

√3+i = 2e^(i π/6),1-√3i = 2e^(i - π/3 ),

所以结果变为 2^14*e^(i π/3 ) / [2^8 * e ^( - 2π/3 ) ] = 2^6 * e^(i π) = - 64