Question

根号下(2x-x的平方)怎么求导?

Answer 1

由y=√2x-x²

则y'=（√(2x-x²)）'

=1/[2√(2x-x²)]*(2x-x²)'

=1/[2√(2x-x²)]*(2-2x)

=(1-x)/√(2x-x²)