Question

数学极限问题?lim(h->0)=h-sin(h)/h^2极限怎么求?,写出具体过程!

Answer 1

lim(h->0)(h-sinh)/h² 0/0型 利用洛必达法则

=lim(h->0)(1-cosh)/2h

=lim(h->0)sinh/2

=0.