Question

过程一定要完整!每一步都要有2(x-3)^2+(3x-x^2)=01/2x(x-2)=x^2-4x+4

Answer 1

2(x-3)^2+(3x-x^2)=0

2(x-3)^2+(3-x)*x=0

(x-3)[2(x-3)-x]=0

(x-3)[x-6]=0

x=3或者6

1/2x(x-2)=x^2-4x+4

1/2x(x-2)=(x-2)^2

x=2或者1/2x=x-2即x=2或者x=4