因为a⊥b,故a•b=0.
因为a+2b与a-2b的夹角为120°,故cos(a+2b,a-2b)=cos120=-1/2
(a+2b)•(a-2b)/(|a+2b||a-2b|)=-1/2
(a^2-4b^2)/[根号下(a^2+4a•b+4b^2)•根号下(a^2-4a•b+4b^2)]=-1/2
因为a•b=0,有
(a^2-4b^2)/(a^2+4b^2)=-1/2
a^2=4/3b^2
a^2/b^2=4/3
所以|a|/|b|=2/根号3
=2√3/3
因为a⊥b,故a•b=0.
因为a+2b与a-2b的夹角为120°,故cos(a+2b,a-2b)=cos120=-1/2
(a+2b)•(a-2b)/(|a+2b||a-2b|)=-1/2
(a^2-4b^2)/[根号下(a^2+4a•b+4b^2)•根号下(a^2-4a•b+4b^2)]=-1/2
因为a•b=0,有
(a^2-4b^2)/(a^2+4b^2)=-1/2
a^2=4/3b^2
a^2/b^2=4/3
所以|a|/|b|=2/根号3
=2√3/3