求三角函数的定义域,1.求y=2cosx/sinx-cosx的定义域2.求f(x)=1+sinx-cosx/1+cosx

2个回答

  • 1、y=2cosx(sinx+cosx)/[(sinx-cosx)(sinx+cosx)]

    =(2sinxcosx+2cos²x)/(sin²x-cos²x)

    =(sin2x+1+cos2x)/(-cos2x)

    =-(1+sin2x)/cos2x-1

    =-(sinx+cosx)²/[(cosx+sinx)(cosx-sinx)]-1

    =(sinx+cosx)/(sinx-cosx)-1

    =(tanx+1)/(tanx-1)-1

    tanx≠1

    x≠kπ+π/4且x≠kπ+π/2 ,k∈Z

    {x|x∈R且x≠kπ+π/4且x≠kπ+π/2,k∈Z}

    2、f(x)=(1+sinx-cosx)/(1+cosx+sinx)

    =[2sin²(x/2)+2sin(x/2)cos(x/2)]/[2cos²(x/2)+2sin(x/2)cos(x/2)]

    =sin(x/2)[sin(x/2)+cos(x/2)]/{cos(x/2)[sin(x/2)+cos(x/2)]}

    =sin(x/2)/cos(x/2)

    =tan(x/2)

    x/2≠kπ+π/2

    x≠2kπ+π

    定义域:{x|x∈R且x≠2kπ+π,k∈Z}