已知复合函数的导函数求原复合函数!

1个回答

复合函数为f(x) f'(x)=2sin(0.5x+0.75pi)
f(x)=∫f'(x)dx=∫2sin(0.5x+0.75pi)dx=2*2∫sin(0.5x+0.75pi)d(0.5x+0.75pi)=-4cos(0.5x+0.75pi)
就是求积分的过程