若(3x+1)5=ax5+bx4+cx3+dx2+ex+f,则a-b+c-d+e-f的值是______.
2个回答
因为(-1)的奇数次方是(-1),如果用1就不会出现负号了。把x等于-1带入原式
得 (-3+1)^5=-a+b-c+d-e+f 则a-b+c-d+e-f=(2)^5=32
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解题求值题若(3x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求a-b+c-d+e-f的值
ax5+bx4+cx3+dx2+ex+f=(x-1)5 求-a+b-c+d-e+f的值.求b+d+f的值