设3x=2y=5z=k
∴x=k/3,y=k/2,z=k/5
（x+2y+3z)÷(x-y+z)
=(k/3+2k/2+3k/5)÷(k/3-k/2+k/5)
=29k/15 ÷ k/30
=58.
已知3x=2y=5z≠0,求（x+2y+3z)÷(x-y+z)
2个回答
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