Question

已知a=5,b=－0.2,n为自然数,求a的（2n＋2）次幂×b的2n次幂×b的3次幂求详细~

Answer 1

a*(2n+2)·b*(2n)·b*3

=5^(2n+2)·(-1/5)^(2n)·(-1/5)^3

=-5^(2n+2)·(1/5)^(2n)·(1/5)^3

=-5^(2n+2)·5^(-2n)·5^(-3)

=-5^(2n+2-2n-3)

=-5^(-1)

=-1/5