Question

已知弧两点距离,弧的高度,问弧长

Answer 1

L=19000mm=19m

H=1500mm=1.5m

弧半径R=(L^2+4*H^2)/(8*H)

=(19^2+4*1.5^2)/(8*1.5)

=370/12=30.833m

中心角=2*ARC SIN((4*HL)/(L^2+4*H^2))

=2*ARC SIN((4*19*1.5)/(19^2+4*1.5^2))

=2*ARC SIN(114/370)

=35.89度=0.6264弧度

弧长C=RA=30.833*0.6264弧度=18.314m