解
2y+x/2=10——这个吗?
两边乘以2得:
4y+x=20
[(2x+y)(2x-y)+(x+y)²-2(2x²-xy)]
=[(4x²-y²)+(x²+2xy+y²)-(4x²-2xy)]
=(4x²+x²-4x²)+(-y²+y²)+(2xy+2xy)
=x²+4xy
=x(x+4y)
=20x
解
2y+x/2=10——这个吗?
两边乘以2得:
4y+x=20
[(2x+y)(2x-y)+(x+y)²-2(2x²-xy)]
=[(4x²-y²)+(x²+2xy+y²)-(4x²-2xy)]
=(4x²+x²-4x²)+(-y²+y²)+(2xy+2xy)
=x²+4xy
=x(x+4y)
=20x