(a-1分之a+1 + a的平方-2a+1分之1) 除以 a-1分之a
=[(a+1)/(a-1)+1/(a-1)²]×(a-1)/a
=[(a+1)(a-1)/(a-1)²+1/(a-1)²]×(a-1)/a
=a²/(a-1)²×(a-1)/a
=a/(a-1)
(a-1分之a+1 + a的平方-2a+1分之1) 除以 a-1分之a
=[(a+1)/(a-1)+1/(a-1)²]×(a-1)/a
=[(a+1)(a-1)/(a-1)²+1/(a-1)²]×(a-1)/a
=a²/(a-1)²×(a-1)/a
=a/(a-1)