Question

已知O是坐标原点,点A在第一象限,向量|OA|=4倍根号3,∠xOA=60°,求向量OA的坐标

Answer 1

let OA(x,y)

|OA|=4√3

x^2+y^2 = 48 (1)

y/x = tan60°

y = √3x (2)

sub(2) into (1)

x^2+3x^2=48

x^2 =12

x= 2√3

y= 6

OA=(2√3,6)