2MnO4- + 10Cl- + 16H+ = 2Mn2+ + 5Cl2 + 8H2O题给条件为标准状态,故：Eθ = φθ(MnO4-/Mn2+) - φθ(Cl2/Cl-) = 1.491V - 1.358V = 0.133VlgKθ = nEθ / 0.059 = 10×0.133 / 0.059 = 22.54∴ Kθ = 3.47×10^22...
2MnO4- + 10Cl- + 16H+ = 2Mn2+ + 5Cl2 + 8H2O题给条件为标准状态,故：Eθ = φθ(MnO4-/Mn2+) - φθ(Cl2/Cl-) = 1.491V - 1.358V = 0.133VlgKθ = nEθ / 0.059 = 10×0.133 / 0.059 = 22.54∴ Kθ = 3.47×10^22...