Question

（2014•东昌府区二模）化简[a+1a2−2a+1

Answer 1

原式=[a+1

(a−1)2+

a−1+2/a−1]

=

a+1

(a−1)2+

a2−1

(a−1)2

=

a+1+a2−1

(a−1)2

=

a(a+1)

(a−1)2．

故答案是：

a(a+1)

(a−1)2．