Question

（1）请认真观察下列等式,根据你发现的规律将第四个等式补写出来

Answer 1

解;规律; n(n+1)(n+2)(n+3)+1=(n*(n+3)+1)^2

说明：n(n+1)(n+2)(n+3)+1

=n(n+3)(n+1)(n+2)+1

=(n^2+3n)(n^2+3n+2)+1

= (n^2+3n)^2+2(n^2+3n)+1

=((n^2+3n)^2+1)^2