若(x+y-5)²+根号下x-y+1=0,求-4x - 知识问答

若(x+y-5)²+根号下x-y+1=0,求-4x+3y的算术平方根

2个回答

∵(x+y-5)²+√（x-y+1）=0
∴x+y-5=0,x-y+1=0得x=2,y=3
故√（-4x+3y）=√1=1

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