显然题目中n∈N
当n=1时,a1=1/2+1/4=3/4<1,命题成立;
假定n=k时,ak<k
当n=k+1时,a(k+1)=ak+(ak)^2/(k+1)^2
<k+[k/(k+1)]^2<k+[(k+1)/(k+1)]^2=k+1,即n=k+1时命题也成立
于是对于n∈N,an<n.
显然题目中n∈N
当n=1时,a1=1/2+1/4=3/4<1,命题成立;
假定n=k时,ak<k
当n=k+1时,a(k+1)=ak+(ak)^2/(k+1)^2
<k+[k/(k+1)]^2<k+[(k+1)/(k+1)]^2=k+1,即n=k+1时命题也成立
于是对于n∈N,an<n.