Question

3/1-x=x/x-1-5 因式分解

Answer 1

x/(x+3)+6/(x²-9)=1/(x-3)

x(x-3)/[(x+3)(x-3)]+6/[(x+3)(x-3)]=(x+3)/[(x+3)(x-3)]

(x²-3x+6-x-3)/[(x+3)(x-3)]=0

(x²-2x-3)/[(x+3)(x-3)]=0

[(x+1)(x-3)]/[(x+3)(x-3)]=0

(x+1)/(x+3)=0

x=1