f(x)=-x^3-2x+1
f'(x)= -3x^2-2
There is no solution for f'(x)=0
=> no turning point
f(0）= 1 >0
f(1) = -2< 0
零点所在 (0,1)
求函数f(x)=--x^3-2x+1零点所在的大致区间,注明详细方法
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f(x)=-x^3-2x+1
f'(x)= -3x^2-2
There is no solution for f'(x)=0
=> no turning point
f(0）= 1 >0
f(1) = -2< 0
零点所在 (0,1)