Question

已知(3X+2)/(X-1)平方=A/（X-1）+B/（X-1）平方,求A和B的值

Answer 1

(3X+2)/(X-1)²=A/（X-1）+B/（X-1）²

(3X+2)/(X-1)²=A(x-1)/（X-1）²+B/（X-1）²

(3X+2)/(X-1)²=[A(x-1)+B]/（X-1）²

3x+2=A(x-1)+B

3x+2=Ax-A+B

A=3

-A+B=2

B=5