Question

如图,A为x轴正半轴上一点,C为y轴正半轴上一点,∠B=∠ACB,DC⊥BC

Answer 1

(1)∵CD平分∠ACO∴∠ACD=∠OCD∵CD⊥BC∴∠ACD+∠ACB=90°∵∠ACB=∠B,∠ACD=∠OCD∴∠OCD+∠ACD+∠ACB+∠B=∠OCB+∠B=180°∴OC//AB(2)∠EHG/（∠BCO+∠PMB）=1/2连AC交EF于D,BC交EP于N,交EF于Q则∠EHG=∠CBG+∠BQ...