Question

解方程：x平方+2x+2=6/(x+1)平方

Answer 1

x²+2x+2=6/(x+1)²

(x+1)²+1=6/(x+1)²

令t=(x+1)²,则：t≧0

原方程化为：t+1=6/t

t²+t-6=0

(t+3)(t-2)=0

t1=-3（舍去）t2=2

即：(x+1)²=2

x+1=±√2

x=-1±√2

即：x1=-1-√2,x2=-1+√2