ac=b^2
根据余弦定理有:
a^2=b^2+c^2-2bccosA
a^2-c^2=b^2-2bccosA
而:b^2=ac,a^2-c^2=ac-bc
所以:ac-bc=ac-2bccosA
cosA=1/2
A=60°
而:b/sinB=a/sinA
sinB=bsinA/a
bsinB/c=(b^2)sinA/(ac)=sinA=(根号3)/2
ac=b^2
根据余弦定理有:
a^2=b^2+c^2-2bccosA
a^2-c^2=b^2-2bccosA
而:b^2=ac,a^2-c^2=ac-bc
所以:ac-bc=ac-2bccosA
cosA=1/2
A=60°
而:b/sinB=a/sinA
sinB=bsinA/a
bsinB/c=(b^2)sinA/(ac)=sinA=(根号3)/2