Question

200ml 0.2mol/L的HCl与100ml 0.1mol/L的NaOH混合后,氢离子浓度为多少?

Answer 1

n(H+)=0.2X0.2=0.04mol

n(OH-)=0.1X0.1=0.01mol

H+ +OH-=H2O

反应后氢离子剩余0.04-0.01=0.03mol

氢离子浓度c(H+)=0.03/(200+100)X1000=0.1mol/L

答氢离子浓度为0.1mol/L