1.由条件1有f(1,1)=2,由条件2知f(m,n+1)=f(m,n)+3,即当m固定时,f(m,n)成等差数列.
∴f(m,n)=f(m,1)+3(n-1).
故c=f(1,1)+3(n-1)=3n-1.
2.由条件知f(m+1,1)=2f(m,1),即f(m,1)是一等比数列.
∴f(m,1)=f(1,1)·2的m-1次方=2的m次方.
f(m,n)=f(m,1)+3(n-1)=2的m次方+3n-3.
1.由条件1有f(1,1)=2,由条件2知f(m,n+1)=f(m,n)+3,即当m固定时,f(m,n)成等差数列.
∴f(m,n)=f(m,1)+3(n-1).
故c=f(1,1)+3(n-1)=3n-1.
2.由条件知f(m+1,1)=2f(m,1),即f(m,1)是一等比数列.
∴f(m,1)=f(1,1)·2的m-1次方=2的m次方.
f(m,n)=f(m,1)+3(n-1)=2的m次方+3n-3.