解
2(x-1)²-x+1
=2(x-1)²-(x-1)
=(x-1)[(2(x-1)-1]
=(x-1)(2x-3)
x的4次方-y的4次方
=(x²)²-(y²)²
=(x²-y²)(x²+y²)
=(x-y)(x+y)(x²+y²)