x=1 y=2 z=7
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
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3x+2y+z=14 { x+y+z=10 2x+3y-z=1
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3x+2y=14,x+y+z=10,2x+3y-z=1
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解方程组{x+y+z=5 ① {x-y-5z=1 ② {2x-3y+z=14 ③ 急
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(1){x+2y+3z=14① {2x+y+z=7②{3x+y+2z=11③
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x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求x y z
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