1/x-1/y=2时
(y-x)/xy=2
y-x=2xy
2x+3xy-2y/x-2xy-y
=[3xy-2(y-x)]/[-2xy-(y-x)]
=-xy/-4xy
=1/4
当1/x-1/y=2时,求分式2x+3xy-2y/x-2xy-y的值
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