f(x)=6cos^x-√3sin2x
＝6·（cos2x+1)/2-√3sin2x
＝3cos2x-√3sin2x＋3
＝2√3cos(2x+π/6)+3
函数的最小正周期为T=π
由| x |
设f(x)=6cos^x-根号3sin2x,(| x |
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