已知(x-3)^2+丨3y+1丨=0.求3x^2y - 知识问答

已知(x-3)^2+丨3y+1丨=0.求3x^2y-[2xy-2(xy-3/2)+xy]+3xy^2的值

2个回答

已知(x-3)^2+丨3y+1丨=0.
x-3=0 x=3
3y+1=0 y=-1/3
3x^2y-[2xy-2(xy-3/2)+xy]+3xy^2
=3x^2y-2xy+2xy-3-xy+3xy^2
=3x^2y-3-xy+3xy^2
=xy(3x-1+3y)
=3×1/3×（3×3-1+3×1/3）
=1×（9-1+1）
=9

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