设A城运了x吨化肥至张村,则A城运了200-x吨化肥至李村,
则B城运了220-x吨化肥至张村,B城运了280-(200-x) = 80+x吨化肥至李村
总费用为 20x+25(200-x)+15(220-x)+22(80+x)
=> 20x+5000-25x+3300-15x+1760+22x
=> 2x+10060
当x=0时总费用为最小值10...
设A城运了x吨化肥至张村,则A城运了200-x吨化肥至李村,
则B城运了220-x吨化肥至张村,B城运了280-(200-x) = 80+x吨化肥至李村
总费用为 20x+25(200-x)+15(220-x)+22(80+x)
=> 20x+5000-25x+3300-15x+1760+22x
=> 2x+10060
当x=0时总费用为最小值10...