Question

解一元二次方程(x²-2x)²=1

Answer 1

解由(x^2-2x)^2=1

得x^2-2x=1或x^2-2x=-1

即x^2-2x-1=0或x^2-2x+1=0

即x1=（2+√8）/2或x2=（2-√8）/2或（x-1）^2=0

即x1=1+√2或x2=1-√2或x3=x4=1.