(1)sinC/(sinBcosA)=c/(bcosA)=2c/b
cosA=1/2
A=pai/3
(2)sinA=sinpai/3=根号3/2
S=1/2bcsinA=1/2*4c*根号3/2=2根号3,c=2
cosA=1/2=(b^2+c^2-a^2)/(2bc)=(16+4-a^2)/16
解得a=2根号3
(1)sinC/(sinBcosA)=c/(bcosA)=2c/b
cosA=1/2
A=pai/3
(2)sinA=sinpai/3=根号3/2
S=1/2bcsinA=1/2*4c*根号3/2=2根号3,c=2
cosA=1/2=(b^2+c^2-a^2)/(2bc)=(16+4-a^2)/16
解得a=2根号3