Question

4a^2x^4y^5-9b^4z^2=?1/3m^2-3n^2=?a^2(a-2b)^2-36=?

Answer 1

4a^2x^4y^5-9b^4z^2

错了,假设y次数是6

则=(2ax²y³)²-(3b²z)²

=(2ax²y³+3b²z)(2ax²y³-3b²z)

1/3m^2-3n^2

=1/3(m²-9n²)

=1/3(m+3n)(m-3n)

a^2(a-2b)^2-36

=[a(a-2b)+6][a(a-2b)-6]

=(a²-2ab+6)(a²-2ab-6)