Question

解方程二元二次方程只有两个式子：、5*(t^2)=(4/9)*h5*((t+1)^2)=h 求t,h解.谢

Answer 1

5*(t^2)=(4/9)*5*((t+1)^2)

=20/9(t^2+2t+1)

45*t^2=20*t^2+40*t+20

25*t^2-40*t-20=0

5*t^2-8*t-4=0

(5t+2)(t-2)=0

t=-2/5 or t=2

h=9/5 or h=45