Question

a=log1/2^3,b=log1/3^2,c=(1/2)^0.3,则abc大小关系

Answer 1

a=log1/2^3,

=-3log2=-3*0.301=-0.903

b=log1/3^2,

=-2log3=2*0.4771=-0.9544

c=(1/2)^0.3

=-2^0.3=-8(开10次方)= -1.231

a＞b＞c