Question

关于二次函数y=x^2-(k-1)-4(k+5) OA:OB=1:4 如图 就K=多少

Answer 1

楼主应该打错了吧~原始应该是y=x^2-(k-1)x-4(k+5)

x1={k-1+√[(k-1)^2+16(k+5)]}/2

x2={k-1-√[(k-1)^2+16(k+5)]}/2

依题意

x2:x1=—1:4

{k-1+√[(k-1)^2+16(k+5)]}/{k-1-√[(k-1)^2+16(k+5)]}=—1/4

然后下面就是繁琐的解方程任务了~